6(1-3b)=-7(3b-6)

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Solution for 6(1-3b)=-7(3b-6) equation: 



6(1-3b)=-7(3b-6)

We move all terms to the left:

6(1-3b)-(-7(3b-6))=0

We add all the numbers together, and all the variables

6(-3b+1)-(-7(3b-6))=0

We multiply parentheses

-18b-(-7(3b-6))+6=0



We calculate terms in parentheses: -(-7(3b-6)), so:

-7(3b-6)

We multiply parentheses

-21b+42

Back to the equation:

-(-21b+42)



We get rid of parentheses

-18b+21b-42+6=0

We add all the numbers together, and all the variables

3b-36=0

We move all terms containing b to the left, all other terms to the right

3b=36

b=36/3

b=12

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