b-5(2b-3)=8(-2b+8)

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Solution for b-5(2b-3)=8(-2b+8) equation: 



b-5(2b-3)=8(-2b+8)

We move all terms to the left:

b-5(2b-3)-(8(-2b+8))=0

We multiply parentheses

b-10b-(8(-2b+8))+15=0



We calculate terms in parentheses: -(8(-2b+8)), so:

8(-2b+8)

We multiply parentheses

-16b+64

Back to the equation:

-(-16b+64)



We add all the numbers together, and all the variables

-9b-(-16b+64)+15=0

We get rid of parentheses

-9b+16b-64+15=0

We add all the numbers together, and all the variables

7b-49=0

We move all terms containing b to the left, all other terms to the right

7b=49

b=49/7

b=7

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