6(1+4b)+6(b+1)=-78

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Solution for 6(1+4b)+6(b+1)=-78 equation: 



6(1+4b)+6(b+1)=-78

We move all terms to the left:

6(1+4b)+6(b+1)-(-78)=0

We add all the numbers together, and all the variables

6(4b+1)+6(b+1)-(-78)=0

We add all the numbers together, and all the variables

6(4b+1)+6(b+1)+78=0

We multiply parentheses

24b+6b+6+6+78=0

We add all the numbers together, and all the variables

30b+90=0

We move all terms containing b to the left, all other terms to the right

30b=-90

b=-90/30

b=-3

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