6y+2(y-9)=5(y+1)-3

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Solution for 6y+2(y-9)=5(y+1)-3 equation: 



6y+2(y-9)=5(y+1)-3

We move all terms to the left:

6y+2(y-9)-(5(y+1)-3)=0

We multiply parentheses

6y+2y-(5(y+1)-3)-18=0



We calculate terms in parentheses: -(5(y+1)-3), so:

5(y+1)-3

We multiply parentheses

5y+5-3

We add all the numbers together, and all the variables

5y+2

Back to the equation:

-(5y+2)



We add all the numbers together, and all the variables

8y-(5y+2)-18=0

We get rid of parentheses

8y-5y-2-18=0

We add all the numbers together, and all the variables

3y-20=0

We move all terms containing y to the left, all other terms to the right

3y=20

y=20/3

y=6+2/3

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