6(1+3r)=6(2r+1)

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Solution for 6(1+3r)=6(2r+1) equation: 



6(1+3r)=6(2r+1)

We move all terms to the left:

6(1+3r)-(6(2r+1))=0

We add all the numbers together, and all the variables

6(3r+1)-(6(2r+1))=0

We multiply parentheses

18r-(6(2r+1))+6=0



We calculate terms in parentheses: -(6(2r+1)), so:

6(2r+1)

We multiply parentheses

12r+6

Back to the equation:

-(12r+6)



We get rid of parentheses

18r-12r-6+6=0

We add all the numbers together, and all the variables

6r=0

r=0/6

r=0

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