6(1+3r)=20r-18-4r

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Solution for 6(1+3r)=20r-18-4r equation: 



6(1+3r)=20r-18-4r

We move all terms to the left:

6(1+3r)-(20r-18-4r)=0

We add all the numbers together, and all the variables

6(3r+1)-(16r-18)=0

We multiply parentheses

18r-(16r-18)+6=0

We get rid of parentheses

18r-16r+18+6=0

We add all the numbers together, and all the variables

2r+24=0

We move all terms containing r to the left, all other terms to the right

2r=-24

r=-24/2

r=-12

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