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6(1+1/2x)=2(x-1)
We move all terms to the left:
6(1+1/2x)-(2(x-1))=0
Domain of the equation: 2x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
6(1/2x+1)-(2(x-1))=0
We multiply parentheses
6x-(2(x-1))+6=0
We calculate terms in parentheses: -(2(x-1)), so:We get rid of parentheses
2(x-1)
We multiply parentheses
2x-2
Back to the equation:
-(2x-2)
6x-2x+2+6=0
We add all the numbers together, and all the variables
4x+8=0
We move all terms containing x to the left, all other terms to the right
4x=-8
x=-8/4
x=-2
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