5(2n+3)=4(5n-1)

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Solution for 5(2n+3)=4(5n-1) equation: 



5(2n+3)=4(5n-1)

We move all terms to the left:

5(2n+3)-(4(5n-1))=0

We multiply parentheses

10n-(4(5n-1))+15=0



We calculate terms in parentheses: -(4(5n-1)), so:

4(5n-1)

We multiply parentheses

20n-4

Back to the equation:

-(20n-4)



We get rid of parentheses

10n-20n+4+15=0

We add all the numbers together, and all the variables

-10n+19=0

We move all terms containing n to the left, all other terms to the right

-10n=-19

n=-19/-10

n=1+9/10

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