6(-z)=29

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Solution for 6(-z)=29 equation: 



6(-z)=29

We move all terms to the left:

6(-z)-(29)=0

We add all the numbers together, and all the variables

6(-1z)-29=0

We multiply parentheses

-6z-29=0

We move all terms containing z to the left, all other terms to the right

-6z=29

z=29/-6

z=-4+5/6

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