6(+-5)=4(t+3)

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Solution for 6(+-5)=4(t+3) equation: 



6(+-5)=4(t+3)

We move all terms to the left:

6(+-5)-(4(t+3))=0

We add all the numbers together, and all the variables

-(4(t+3))+6(-5)=0

We add all the numbers together, and all the variables

-(4(t+3))-30=0



We calculate terms in parentheses: -(4(t+3)), so:

4(t+3)

We multiply parentheses

4t+12

Back to the equation:

-(4t+12)



We get rid of parentheses

-4t-12-30=0

We add all the numbers together, and all the variables

-4t-42=0

We move all terms containing t to the left, all other terms to the right

-4t=42

t=42/-4

t=-10+1/2

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