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5z^2-22z+8=0
a = 5; b = -22; c = +8;
Δ = b2-4ac
Δ = -222-4·5·8
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{324}=18$$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-22)-18}{2*5}=\frac{4}{10} =2/5 $$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-22)+18}{2*5}=\frac{40}{10} =4 $
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