(3p+2)(p+5)=0

Solution for (3p+2)(p+5)=0 equation:

(3p+2)(p+5)=0

We multiply parentheses ..

(+3p^2+15p+2p+10)=0

We get rid of parentheses

3p^2+15p+2p+10=0

We add all the numbers together, and all the variables

3p^2+17p+10=0

a = 3; b = 17; c = +10;
Δ = b2-4ac
Δ = 172-4·3·10
Δ = 169
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{169}=13$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(17)-13}{2*3}=\frac{-30}{6}
=-5
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(17)+13}{2*3}=\frac{-4}{6}
=-2/3
$