5z+4=-3(2z-5)

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Solution for 5z+4=-3(2z-5) equation: 



5z+4=-3(2z-5)

We move all terms to the left:

5z+4-(-3(2z-5))=0



We calculate terms in parentheses: -(-3(2z-5)), so:

-3(2z-5)

We multiply parentheses

-6z+15

Back to the equation:

-(-6z+15)



We get rid of parentheses

5z+6z-15+4=0

We add all the numbers together, and all the variables

11z-11=0

We move all terms containing z to the left, all other terms to the right

11z=11

z=11/11

z=1

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