3(d-5)+d=1

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Solution for 3(d-5)+d=1 equation:



3(d-5)+d=1
We move all terms to the left:
3(d-5)+d-(1)=0
We add all the numbers together, and all the variables
d+3(d-5)-1=0
We multiply parentheses
d+3d-15-1=0
We add all the numbers together, and all the variables
4d-16=0
We move all terms containing d to the left, all other terms to the right
4d=16
d=16/4
d=4

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