3(x+1)=2(X+1)+6

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Solution for 3(x+1)=2(X+1)+6 equation: 



3(x+1)=2(x+1)+6

We move all terms to the left:

3(x+1)-(2(x+1)+6)=0

We multiply parentheses

3x-(2(x+1)+6)+3=0



We calculate terms in parentheses: -(2(x+1)+6), so:

2(x+1)+6

We multiply parentheses

2x+2+6

We add all the numbers together, and all the variables

2x+8

Back to the equation:

-(2x+8)



We get rid of parentheses

3x-2x-8+3=0

We add all the numbers together, and all the variables

x-5=0

We move all terms containing x to the left, all other terms to the right

x=5

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