F=5/4(n-67)

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Solution for F=5/4(n-67) equation: 



=5/4(F-67)

We move all terms to the left:

-(5/4(F-67))=0



Domain of the equation: 4(F-67))!=0

F∈R



We multiply all the terms by the denominator


-(5=0

We add all the numbers together, and all the variables

=0

F=0/1

F=0

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