5z+2(z-4)=27

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Solution for 5z+2(z-4)=27 equation: 



5z+2(z-4)=27

We move all terms to the left:

5z+2(z-4)-(27)=0

We multiply parentheses

5z+2z-8-27=0

We add all the numbers together, and all the variables

7z-35=0

We move all terms containing z to the left, all other terms to the right

7z=35

z=35/7

z=5

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