4(y+1)=y+18

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Solution for 4(y+1)=y+18 equation: 



4(y+1)=y+18

We move all terms to the left:

4(y+1)-(y+18)=0

We multiply parentheses

4y-(y+18)+4=0

We get rid of parentheses

4y-y-18+4=0

We add all the numbers together, and all the variables

3y-14=0

We move all terms containing y to the left, all other terms to the right

3y=14

y=14/3

y=4+2/3

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