5z(1/z)=(6/5z+1)5z

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Solution for 5z(1/z)=(6/5z+1)5z equation: 



5z(1/z)=(6/5z+1)5z

We move all terms to the left:

5z(1/z)-((6/5z+1)5z)=0



Domain of the equation: z)!=0

z!=0/1

z!=0

z∈R





Domain of the equation: 5z+1)5z)!=0

z∈R



We add all the numbers together, and all the variables

5z(+1/z)-((6/5z+1)5z)=0

We multiply parentheses

5z^2-((6/5z+1)5z)=0

We multiply all the terms by the denominator


5z^2*5z+1)5z)-((6=0

Wy multiply elements

25z^3+1)5z)-((6=0

We do not support ezpression: z^3

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