5z(-2z+5)=

Solution for 5z(-2z+5)= equation:

5z(-2z+5)=

We move all terms to the left:

5z(-2z+5)-()=0

We add all the numbers together, and all the variables

5z(-2z+5)=0

We multiply parentheses

-10z^2+25z=0

a = -10; b = 25; c = 0;
Δ = b2-4ac
Δ = 252-4·(-10)·0
Δ = 625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{625}=25$
$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(25)-25}{2*-10}=\frac{-50}{-20}
=2+1/2
$
$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(25)+25}{2*-10}=\frac{0}{-20}
=0
$