(28-4x)-(6x-6)=10x-20

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Solution for (28-4x)-(6x-6)=10x-20 equation: 



(28-4x)-(6x-6)=10x-20

We move all terms to the left:

(28-4x)-(6x-6)-(10x-20)=0

We add all the numbers together, and all the variables

(-4x+28)-(6x-6)-(10x-20)=0

We get rid of parentheses

-4x-6x-10x+28+6+20=0

We add all the numbers together, and all the variables

-20x+54=0

We move all terms containing x to the left, all other terms to the right

-20x=-54

x=-54/-20

x=2+7/10

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