5y=3(y-1)+2y+3

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Solution for 5y=3(y-1)+2y+3 equation: 



5y=3(y-1)+2y+3

We move all terms to the left:

5y-(3(y-1)+2y+3)=0



We calculate terms in parentheses: -(3(y-1)+2y+3), so:

3(y-1)+2y+3

We add all the numbers together, and all the variables

2y+3(y-1)+3

We multiply parentheses

2y+3y-3+3

We add all the numbers together, and all the variables

5y

Back to the equation:

-(5y)



We add all the numbers together, and all the variables

=0

y=0/1

y=0

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