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-2m+2=1/5m+11
We move all terms to the left:
-2m+2-(1/5m+11)=0
Domain of the equation: 5m+11)!=0We get rid of parentheses
m∈R
-2m-1/5m-11+2=0
We multiply all the terms by the denominator
-2m*5m-11*5m+2*5m-1=0
Wy multiply elements
-10m^2-55m+10m-1=0
We add all the numbers together, and all the variables
-10m^2-45m-1=0
a = -10; b = -45; c = -1;
Δ = b2-4ac
Δ = -452-4·(-10)·(-1)
Δ = 1985
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-45)-\sqrt{1985}}{2*-10}=\frac{45-\sqrt{1985}}{-20} $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-45)+\sqrt{1985}}{2*-10}=\frac{45+\sqrt{1985}}{-20} $
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