5y-8+2(3y+6)=-3(y+2)

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Solution for 5y-8+2(3y+6)=-3(y+2) equation: 



5y-8+2(3y+6)=-3(y+2)

We move all terms to the left:

5y-8+2(3y+6)-(-3(y+2))=0

We multiply parentheses

5y+6y-(-3(y+2))+12-8=0



We calculate terms in parentheses: -(-3(y+2)), so:

-3(y+2)

We multiply parentheses

-3y-6

Back to the equation:

-(-3y-6)



We add all the numbers together, and all the variables

11y-(-3y-6)+4=0

We get rid of parentheses

11y+3y+6+4=0

We add all the numbers together, and all the variables

14y+10=0

We move all terms containing y to the left, all other terms to the right

14y=-10

y=-10/14

y=-5/7

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