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(2x+1)+x=(x+1)+(x+2)
We move all terms to the left:
(2x+1)+x-((x+1)+(x+2))=0
We add all the numbers together, and all the variables
x+(2x+1)-((x+1)+(x+2))=0
We get rid of parentheses
x+2x-((x+1)+(x+2))+1=0
We calculate terms in parentheses: -((x+1)+(x+2)), so:We add all the numbers together, and all the variables
(x+1)+(x+2)
We get rid of parentheses
x+x+1+2
We add all the numbers together, and all the variables
2x+3
Back to the equation:
-(2x+3)
3x-(2x+3)+1=0
We get rid of parentheses
3x-2x-3+1=0
We add all the numbers together, and all the variables
x-2=0
We move all terms containing x to the left, all other terms to the right
x=2
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