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5y-6=4-10(y-3)
We move all terms to the left:
5y-6-(4-10(y-3))=0
We calculate terms in parentheses: -(4-10(y-3)), so:We get rid of parentheses
4-10(y-3)
determiningTheFunctionDomain -10(y-3)+4
We multiply parentheses
-10y+30+4
We add all the numbers together, and all the variables
-10y+34
Back to the equation:
-(-10y+34)
5y+10y-34-6=0
We add all the numbers together, and all the variables
15y-40=0
We move all terms containing y to the left, all other terms to the right
15y=40
y=40/15
y=2+2/3
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