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+4=1/3(Y-1)
We move all terms to the left:
+4-(1/3(Y-1))=0
Domain of the equation: 3(Y-1))!=0We multiply all the terms by the denominator
Y∈R
-(1+4*3(Y-1))=0
We calculate terms in parentheses: -(1+4*3(Y-1)), so:
1+4*3(Y-1)
determiningTheFunctionDomain 4*3(Y-1)+1
Wy multiply elements
12Y(Y+1
Back to the equation:
-(12Y(Y+1)
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| s/12=16.85 | | j16=8 | | 2(5x+4)=3(2x+1)+4 | | 3w^+2=-7w | | 7x+3=15+1 | | 22=x/2+7 | | 7x^2-14x=49 | | 5/3-2D=5/6d-d+3 | | 13y-8=3y | | 13-8=3y | | 12v-6+5v=-29 | | c+1/4=7/12 | | -25h=600 | | 3/4=165/x | | 12c=14 | | 4x+30=6x*20 | | 5-2d=13 | | 6x(1/2x)+3x=8 | | 2.5x+x=28 | | (17-5)(+6)=3x-12 | | 20+2x=5x-16 | | 2x4+5=6 | | 2x=4/5=6 | | -9(e-6)=18 | | 6k+1=9+8(k-5) | | 5x-15-15x-60=0 | | 13-2x=8+4x | | 9x2-24x=-20 | | 2e-5=6 | | 8x+8=10-4x | | 4x+3(x+4=5x+10 | | 26.8=8+4m |