5y-6+2(3y+1)=-7(y+1)

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Solution for 5y-6+2(3y+1)=-7(y+1) equation: 



5y-6+2(3y+1)=-7(y+1)

We move all terms to the left:

5y-6+2(3y+1)-(-7(y+1))=0

We multiply parentheses

5y+6y-(-7(y+1))+2-6=0



We calculate terms in parentheses: -(-7(y+1)), so:

-7(y+1)

We multiply parentheses

-7y-7

Back to the equation:

-(-7y-7)



We add all the numbers together, and all the variables

11y-(-7y-7)-4=0

We get rid of parentheses

11y+7y+7-4=0

We add all the numbers together, and all the variables

18y+3=0

We move all terms containing y to the left, all other terms to the right

18y=-3

y=-3/18

y=-1/6

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