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12-3(4-x)=5x-2(x-2)
We move all terms to the left:
12-3(4-x)-(5x-2(x-2))=0
We add all the numbers together, and all the variables
-3(-1x+4)-(5x-2(x-2))+12=0
We multiply parentheses
3x-(5x-2(x-2))-12+12=0
We calculate terms in parentheses: -(5x-2(x-2)), so:We add all the numbers together, and all the variables
5x-2(x-2)
We multiply parentheses
5x-2x+4
We add all the numbers together, and all the variables
3x+4
Back to the equation:
-(3x+4)
3x-(3x+4)=0
We get rid of parentheses
3x-3x-4=0
We add all the numbers together, and all the variables
-4!=0
There is no solution for this equation
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