5y-2(11+4y)+5=15+2(2y-1)-2y

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Solution for 5y-2(11+4y)+5=15+2(2y-1)-2y equation: 



5y-2(11+4y)+5=15+2(2y-1)-2y

We move all terms to the left:

5y-2(11+4y)+5-(15+2(2y-1)-2y)=0

We add all the numbers together, and all the variables

5y-2(4y+11)-(15+2(2y-1)-2y)+5=0

We multiply parentheses

5y-8y-(15+2(2y-1)-2y)-22+5=0



We calculate terms in parentheses: -(15+2(2y-1)-2y), so:

15+2(2y-1)-2y

determiningTheFunctionDomain
2(2y-1)-2y+15

We add all the numbers together, and all the variables

-2y+2(2y-1)+15

We multiply parentheses

-2y+4y-2+15

We add all the numbers together, and all the variables

2y+13

Back to the equation:

-(2y+13)



We add all the numbers together, and all the variables

-3y-(2y+13)-17=0

We get rid of parentheses

-3y-2y-13-17=0

We add all the numbers together, and all the variables

-5y-30=0

We move all terms containing y to the left, all other terms to the right

-5y=30

y=30/-5

y=-6

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