-3y+10=-4(y-2)

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Solution for -3y+10=-4(y-2) equation: 



-3y+10=-4(y-2)

We move all terms to the left:

-3y+10-(-4(y-2))=0



We calculate terms in parentheses: -(-4(y-2)), so:

-4(y-2)

We multiply parentheses

-4y+8

Back to the equation:

-(-4y+8)



We get rid of parentheses

-3y+4y-8+10=0

We add all the numbers together, and all the variables

y+2=0

We move all terms containing y to the left, all other terms to the right

y=-2

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