(17*2=6*2+b*2,b)

Solution for (17*2=6*2+b*2,b) equation:

(17*2=6*2+b*2.b)

We move all terms to the left:

(17*2-(6*2+b*2.b))=0

We add all the numbers together, and all the variables

(17*2-(b*2.b+12))=0


We calculate terms in parentheses: +(17*2-(b*2.b+12)), so:

17*2-(b*2.b+12)

determiningTheFunctionDomain
-(b*2.b+12)+17*2

We add all the numbers together, and all the variables

-(b*2.b+12)+34

We get rid of parentheses

-b*2.b-12+34

We add all the numbers together, and all the variables

-b*2.b+22

Wy multiply elements

-2b^2+22

Back to the equation:

+(-2b^2+22)


We get rid of parentheses

-2b^2+22=0

a = -2; b = 0; c = +22;
Δ = b2-4ac
Δ = 02-4·(-2)·22
Δ = 176
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{176}=\sqrt{16*11}=\sqrt{16}*\sqrt{11}=4\sqrt{11}$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{11}}{2*-2}=\frac{0-4\sqrt{11}}{-4}
=-\frac{4\sqrt{11}}{-4}
=-\frac{\sqrt{11}}{-1}
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{11}}{2*-2}=\frac{0+4\sqrt{11}}{-4}
=\frac{4\sqrt{11}}{-4}
=\frac{\sqrt{11}}{-1}
$