5y-(y+3)=7+(y+2)

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Solution for 5y-(y+3)=7+(y+2) equation: 



5y-(y+3)=7+(y+2)

We move all terms to the left:

5y-(y+3)-(7+(y+2))=0

We get rid of parentheses

5y-y-(7+(y+2))-3=0



We calculate terms in parentheses: -(7+(y+2)), so:

7+(y+2)

determiningTheFunctionDomain
(y+2)+7

We get rid of parentheses

y+2+7

We add all the numbers together, and all the variables

y+9

Back to the equation:

-(y+9)



We add all the numbers together, and all the variables

4y-(y+9)-3=0

We get rid of parentheses

4y-y-9-3=0

We add all the numbers together, and all the variables

3y-12=0

We move all terms containing y to the left, all other terms to the right

3y=12

y=12/3

y=4

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