5y+6-3(-5y-2)=2(y-2)

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Solution for 5y+6-3(-5y-2)=2(y-2) equation: 



5y+6-3(-5y-2)=2(y-2)

We move all terms to the left:

5y+6-3(-5y-2)-(2(y-2))=0

We multiply parentheses

5y+15y-(2(y-2))+6+6=0



We calculate terms in parentheses: -(2(y-2)), so:

2(y-2)

We multiply parentheses

2y-4

Back to the equation:

-(2y-4)



We add all the numbers together, and all the variables

20y-(2y-4)+12=0

We get rid of parentheses

20y-2y+4+12=0

We add all the numbers together, and all the variables

18y+16=0

We move all terms containing y to the left, all other terms to the right

18y=-16

y=-16/18

y=-8/9

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