2u-1+3(2u+4)=-4(u+1)

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Solution for 2u-1+3(2u+4)=-4(u+1) equation: 



2u-1+3(2u+4)=-4(u+1)

We move all terms to the left:

2u-1+3(2u+4)-(-4(u+1))=0

We multiply parentheses

2u+6u-(-4(u+1))+12-1=0



We calculate terms in parentheses: -(-4(u+1)), so:

-4(u+1)

We multiply parentheses

-4u-4

Back to the equation:

-(-4u-4)



We add all the numbers together, and all the variables

8u-(-4u-4)+11=0

We get rid of parentheses

8u+4u+4+11=0

We add all the numbers together, and all the variables

12u+15=0

We move all terms containing u to the left, all other terms to the right

12u=-15

u=-15/12

u=-1+1/4

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