5y+34=2(7y-1)

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Solution for 5y+34=2(7y-1) equation: 



5y+34=2(7y-1)

We move all terms to the left:

5y+34-(2(7y-1))=0



We calculate terms in parentheses: -(2(7y-1)), so:

2(7y-1)

We multiply parentheses

14y-2

Back to the equation:

-(14y-2)



We get rid of parentheses

5y-14y+2+34=0

We add all the numbers together, and all the variables

-9y+36=0

We move all terms containing y to the left, all other terms to the right

-9y=-36

y=-36/-9

y=+4

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