12x-6=3(4x-212x)

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Solution for 12x-6=3(4x-212x) equation: 



12x-6=3(4x-212x)

We move all terms to the left:

12x-6-(3(4x-212x))=0

We add all the numbers together, and all the variables

12x-(3(-208x))-6=0



We calculate terms in parentheses: -(3(-208x)), so:

3(-208x)

We multiply parentheses

-624x

Back to the equation:

-(-624x)



We get rid of parentheses

12x+624x-6=0

We add all the numbers together, and all the variables

636x-6=0

We move all terms containing x to the left, all other terms to the right

636x=6

x=6/636

x=1/106

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