5y+3(3y-7)=42

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Solution for 5y+3(3y-7)=42 equation: 



5y+3(3y-7)=42

We move all terms to the left:

5y+3(3y-7)-(42)=0

We multiply parentheses

5y+9y-21-42=0

We add all the numbers together, and all the variables

14y-63=0

We move all terms containing y to the left, all other terms to the right

14y=63

y=63/14

y=4+1/2

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