3(2t-4)=5(t+3)

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Solution for 3(2t-4)=5(t+3) equation: 



3(2t-4)=5(t+3)

We move all terms to the left:

3(2t-4)-(5(t+3))=0

We multiply parentheses

6t-(5(t+3))-12=0



We calculate terms in parentheses: -(5(t+3)), so:

5(t+3)

We multiply parentheses

5t+15

Back to the equation:

-(5t+15)



We get rid of parentheses

6t-5t-15-12=0

We add all the numbers together, and all the variables

t-27=0

We move all terms containing t to the left, all other terms to the right

t=27

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