5y+2=13+4(2y-1)

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Solution for 5y+2=13+4(2y-1) equation: 



5y+2=13+4(2y-1)

We move all terms to the left:

5y+2-(13+4(2y-1))=0



We calculate terms in parentheses: -(13+4(2y-1)), so:

13+4(2y-1)

determiningTheFunctionDomain
4(2y-1)+13

We multiply parentheses

8y-4+13

We add all the numbers together, and all the variables

8y+9

Back to the equation:

-(8y+9)



We get rid of parentheses

5y-8y-9+2=0

We add all the numbers together, and all the variables

-3y-7=0

We move all terms containing y to the left, all other terms to the right

-3y=7

y=7/-3

y=-2+1/3

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