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1/5(20d+12)=d+7
We move all terms to the left:
1/5(20d+12)-(d+7)=0
Domain of the equation: 5(20d+12)!=0We get rid of parentheses
d∈R
1/5(20d+12)-d-7=0
We multiply all the terms by the denominator
-d*5(20d+12)-7*5(20d+12)+1=0
Wy multiply elements
-5d^2(2-35d(2+1=0
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