5y+2(y-8)=3(y+1)-2

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Solution for 5y+2(y-8)=3(y+1)-2 equation: 


Simplifying
5y + 2(y + -8) = 3(y + 1) + -2

Reorder the terms:
5y + 2(-8 + y) = 3(y + 1) + -2
5y + (-8 * 2 + y * 2) = 3(y + 1) + -2
5y + (-16 + 2y) = 3(y + 1) + -2

Reorder the terms:
-16 + 5y + 2y = 3(y + 1) + -2

Combine like terms: 5y + 2y = 7y
-16 + 7y = 3(y + 1) + -2

Reorder the terms:
-16 + 7y = 3(1 + y) + -2
-16 + 7y = (1 * 3 + y * 3) + -2
-16 + 7y = (3 + 3y) + -2

Reorder the terms:
-16 + 7y = 3 + -2 + 3y

Combine like terms: 3 + -2 = 1
-16 + 7y = 1 + 3y

Solving
-16 + 7y = 1 + 3y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-3y' to each side of the equation.
-16 + 7y + -3y = 1 + 3y + -3y

Combine like terms: 7y + -3y = 4y
-16 + 4y = 1 + 3y + -3y

Combine like terms: 3y + -3y = 0
-16 + 4y = 1 + 0
-16 + 4y = 1

Add '16' to each side of the equation.
-16 + 16 + 4y = 1 + 16

Combine like terms: -16 + 16 = 0
0 + 4y = 1 + 16
4y = 1 + 16

Combine like terms: 1 + 16 = 17
4y = 17

Divide each side by '4'.
y = 4.25

Simplifying
y = 4.25

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