3/n+n/12-6=5+2n-18

Solution for 3/n+n/12-6=5+2n-18 equation:

D( n )

n = 0

n = 0

n = 0

n in (-oo:0) U (0:+oo)

n/12+3/n-6 = 2*n-18+5 // - 2*n-18+5

n/12-(2*n)+3/n-6-5+18 = 0

n/12-2*n+3/n-6-5+18 = 0

3*n^-1-23/12*n^1+7*n^0 = 0

(7*n^1-23/12*n^2+3*n^0)/(n^1) = 0 // * n^2

n^1*(7*n^1-23/12*n^2+3*n^0) = 0

n^1

(-23/12)*n^2+7*n+3 = 0

(-23/12)*n^2+7*n+3 = 0

DELTA = 7^2-(3*4*(-23/12))

DELTA = 72

DELTA > 0

n = (72^(1/2)-7)/(2*(-23/12)) or n = (-72^(1/2)-7)/(2*(-23/12))

n = -6/23*(6*2^(1/2)-7) or n = -6/23*(-6*2^(1/2)-7)

n in { -6/23*(6*2^(1/2)-7), -6/23*(-6*2^(1/2)-7)} 

n in { -6/23*(6*2^(1/2)-7), -6/23*(-6*2^(1/2)-7) }