5y+2(1-y)=2(2y+1)

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Solution for 5y+2(1-y)=2(2y+1) equation: 



5y+2(1-y)=2(2y+1)

We move all terms to the left:

5y+2(1-y)-(2(2y+1))=0

We add all the numbers together, and all the variables

5y+2(-1y+1)-(2(2y+1))=0

We multiply parentheses

5y-2y-(2(2y+1))+2=0



We calculate terms in parentheses: -(2(2y+1)), so:

2(2y+1)

We multiply parentheses

4y+2

Back to the equation:

-(4y+2)



We add all the numbers together, and all the variables

3y-(4y+2)+2=0

We get rid of parentheses

3y-4y-2+2=0

We add all the numbers together, and all the variables

-y=0

y=0/-1

y=0

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