3(z-4)-2=4(z-6)

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Solution for 3(z-4)-2=4(z-6) equation: 



3(z-4)-2=4(z-6)

We move all terms to the left:

3(z-4)-2-(4(z-6))=0

We multiply parentheses

3z-(4(z-6))-12-2=0



We calculate terms in parentheses: -(4(z-6)), so:

4(z-6)

We multiply parentheses

4z-24

Back to the equation:

-(4z-24)



We add all the numbers together, and all the variables

3z-(4z-24)-14=0

We get rid of parentheses

3z-4z+24-14=0

We add all the numbers together, and all the variables

-1z+10=0

We move all terms containing z to the left, all other terms to the right

-z=-10

z=-10/-1

z=+10

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