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2/3x-16+2x-6=90
We move all terms to the left:
2/3x-16+2x-6-(90)=0
Domain of the equation: 3x!=0We add all the numbers together, and all the variables
x!=0/3
x!=0
x∈R
2x+2/3x-112=0
We multiply all the terms by the denominator
2x*3x-112*3x+2=0
Wy multiply elements
6x^2-336x+2=0
a = 6; b = -336; c = +2;
Δ = b2-4ac
Δ = -3362-4·6·2
Δ = 112848
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{112848}=\sqrt{16*7053}=\sqrt{16}*\sqrt{7053}=4\sqrt{7053}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-336)-4\sqrt{7053}}{2*6}=\frac{336-4\sqrt{7053}}{12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-336)+4\sqrt{7053}}{2*6}=\frac{336+4\sqrt{7053}}{12} $
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