10(z+3)-(-9z-4)=z-5+3

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Solution for 10(z+3)-(-9z-4)=z-5+3 equation: 



10(z+3)-(-9z-4)=z-5+3

We move all terms to the left:

10(z+3)-(-9z-4)-(z-5+3)=0

We add all the numbers together, and all the variables

10(z+3)-(-9z-4)-(z-2)=0

We multiply parentheses

10z-(-9z-4)-(z-2)+30=0

We get rid of parentheses

10z+9z-z+4+2+30=0

We add all the numbers together, and all the variables

18z+36=0

We move all terms containing z to the left, all other terms to the right

18z=-36

z=-36/18

z=-2

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