5*t-((t-17)/3)-1=0

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Solution for 5*t-((t-17)/3)-1=0 equation: 



5t-((t-17)/3)-1=0

We multiply all the terms by the denominator


5t*3)-((t-17)-1*3)=0

We add all the numbers together, and all the variables

5t*3)-((t-17)=0

Wy multiply elements

15t^2=0

a = 15; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·15·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$t=\frac{-b}{2a}=\frac{0}{30}=0$

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