5y+-2=1/2*10y

Solution for 5y+-2=1/2*10y equation:

5y+-2=1/2*10y

We move all terms to the left:

5y+-2-(1/2*10y)=0


Domain of the equation: 2*10y)!=0

y!=0/1

y!=0

y∈R


We add all the numbers together, and all the variables

5y-(+1/2*10y)-2+=0

We add all the numbers together, and all the variables

5y-(+1/2*10y)=0

We get rid of parentheses

5y-1/2*10y=0

We multiply all the terms by the denominator


5y*2*10y-1=0

Wy multiply elements

100y^2*1-1=0

Wy multiply elements

100y^2-1=0

a = 100; b = 0; c = -1;
Δ = b2-4ac
Δ = 02-4·100·(-1)
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{400}=20$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-20}{2*100}=\frac{-20}{200}
=-1/10
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+20}{2*100}=\frac{20}{200}
=1/10
$