(6x-12)+88=(3x+21)

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Solution for (6x-12)+88=(3x+21) equation: 



(6x-12)+88=(3x+21)

We move all terms to the left:

(6x-12)+88-((3x+21))=0

We get rid of parentheses

6x-((3x+21))-12+88=0



We calculate terms in parentheses: -((3x+21)), so:

(3x+21)

We get rid of parentheses

3x+21

Back to the equation:

-(3x+21)



We add all the numbers together, and all the variables

6x-(3x+21)+76=0

We get rid of parentheses

6x-3x-21+76=0

We add all the numbers together, and all the variables

3x+55=0

We move all terms containing x to the left, all other terms to the right

3x=-55

x=-55/3

x=-18+1/3

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